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Re: [Sip] Dual registration without Outbound
Subclause 3.1 says the following:
"When a proxy goes to route a message to a UA for which it has a
binding, it can use any one of the flows on which a successful
registration has been completed. A failure to deliver a request on a
particular flow can be tried again on an alternate flow. Proxies can
determine which flows go to the same UA by comparing the
instance-id."
Note that the text says "can use ONE of the flows". So, to me that
doesn't mean that the request will be forked on multiple flows.
Regards,
Christer
-----Original Message-----
From: sip-bounces at ietf.org [mailto:sip-bounces at ietf.org] On Behalf Of
Christer Holmberg
Sent: Monday, October 06, 2008 9:50 AM
To: Juha Heinanen
Cc: sip at ietf.org; dean.willis at softarmor.com
Subject: Re: [Sip] Dual registration without Outbound
Hi,
>>If you want to do that you simply register the same AoR twice using
basic 3261 registration, without Outbound, and the >>inbound call will
be forked.
>
>are you saying that if i use outbound, then the inbound call will NOT
get forked (which would be very bad)?
I thought the whole idea of outbound was that the registrar chooses ONE
flow, and switches to another flow is the previous doesn't work. But, it
does not fork onto multiple flows.
Or, have I missunderstood everything???
Regards,
Christer
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_______________________________________________
Sip mailing list https://www.ietf.org/mailman/listinfo/sip
This list is for NEW development of the core SIP Protocol
Use sip-implementors at cs.columbia.edu for questions on current sip
Use sipping at ietf.org for new developments on the application of sip